L and L are the ends of the latus rectum of the parabola `x^(2)=6y.` The equation of OL and OL where O is the origin is

Find the length of the latus rectum of the parabola x^(2) = -8y .

The length of the latus rectum of the parabola x^(2) = -28y is

The length of the latus rectum of the parabola x^2 - 6x + 5y = 0 is

Find the length of latus rectum of the parabola y^(2) = - 10 x

lf L and L^(1) are ends or latusrectum of the parabola 9y^(2)= 4x then the combined equation of OL and OL^(1) is

The equation of the latus rectum of the parabola x^(2)-12x-8y+52=0 is

Find the vertex and length of latus rectum of the parabola x^(2)=-4(y-a) .

The length of the latus rectum of 3x^(2) - 2y^(2) =6 is

The length of the latus - rectum of the parabola 4y^(2) + 2x - 20 y + 17 = 0 is

Find the equations of the normals at the ends of the latus- rectum of the parabola y^2= 4ax. Also prove that they are at right angles on the axis of the parabola.