If the normal P(8,8) to the parabola `y^(2) = 8x` cuts It again at Q then find the length PQ

The normal at P(8, 8) to the parabola y^(2) = 8x cuts it again at Q then PQ =

If the normal at P(18, 12) to the parabola y^(2)=8x cuts it again at Q, then the equation of the normal at point Q on the parabola y^(2)=8x is

A tangent and a normal are drawn at the point P(8, 8) on the parabola y^(2)=8x which cuts the axis of the parabola at the points A and B respectively. If the centre of the circle through P, A and B is C, then the sum of sin(anglePCB) and cot(anglePCB) is equal to

The line x+y=6 is normal to the parabola y^(2)=8x at the point.

The area of triangle formed by tangent and normal at (8, 8) on the parabola y^(2)=8x and the axis of the parabola is

Two tangents to the parabola y^(2) = 8x meet the tangent at its vertex in the points P & Q. If PQ = 4 units, prove that the locus of the point of the intersection of the two tangents is y^(2) = 8 (x + 2) .

If the normal to the parabola y^2=4a x at point t_1 cuts the parabola again at point t_2 , then prove that (t_2)^2geq8.

If the normal to the parabola y^2=4a x at point t_1 cuts the parabola again at point t_2 , then prove that t2 2geq8.

Consider the parabola y^(2)=8x, if the normal at a point P on the parabola meets it again at a point Q, then the least distance of Q from the tangent at the vertex of the parabola is

Consider the parabola y^(2)=8x, if the normal at a point P on the parabola meets it again at a point Q, then the least distance of Q from the tangent at the vertex of the parabola is