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Find the equation of the parabola whose ...

Find the equation of the parabola whose vertex and focus are on the positive X-axis at a distance of a and a' from the origin respectively.

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To find the equation of the parabola whose vertex and focus are on the positive X-axis at distances \( a \) and \( a' \) from the origin respectively, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Coordinates of the Vertex and Focus:** - The vertex of the parabola is located at \( (a, 0) \). - The focus of the parabola is located at \( (a', 0) \). 2. **Determine the Distance \( p \):** - The distance \( p \) between the vertex and the focus is given by: \[ p = a' - a \] - Here, \( p \) is the distance from the vertex to the focus along the x-axis. 3. **General Form of the Parabola:** - The standard form of a parabola that opens to the right is: \[ (y - k)^2 = 4p(x - h) \] - Where \( (h, k) \) is the vertex of the parabola. 4. **Substituting the Vertex Coordinates:** - In our case, the vertex \( (h, k) \) is \( (a, 0) \). Thus, substituting these values into the equation gives: \[ (y - 0)^2 = 4p(x - a) \] - This simplifies to: \[ y^2 = 4p(x - a) \] 5. **Substituting the Value of \( p \):** - We already found that \( p = a' - a \). Substituting this into the equation gives: \[ y^2 = 4(a' - a)(x - a) \] 6. **Final Equation of the Parabola:** - Therefore, the equation of the parabola is: \[ y^2 = 4(a' - a)(x - a) \]
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