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Find the equation of normal to y^(2)=8x ...

Find the equation of normal to `y^(2)=8x` which is
(i) Perpendicular
(ii) Parallel to the line 2x-4y+5=0

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The correct Answer is:
i ) 2x + y - 24 = 0 ii) 2x-4y-9 =0
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