Home
Class 12
MATHS
The parabola (y+1)^2=a(x-2) passes thro...

The parabola `(y+1)^2=a(x-2)` passes through the poni (1-2) the equation of its directix is a) 4x+1=0 b) 4x-1=0 c) 4x+9=0 d)4x-9=0

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

Let L be a normal to the parabola y^2=4x dot If L passes through the point (9, 6), then L is given by (a) y-x+3=0 (b) y+3x-33=0 (c) y+x-15=0 (d) y-2x+12=0

Let (2,3) be the focus of a parabola and x + y = 0 and x-y= 0 be its two tangents. Then equation of its directrix will be (a) 2x - 3y = 0 (b) 3x +4y = 0 (c) x +y = 5 (d) 12x -5y +1 = 0

If two tangents drawn from a point P to the parabola y^2=4x are at right angles, then the locus of P is (a) 2x+1=0 (b) x=-1 (c) 2x-1=0 (d) x=1

The parametric equations of a parabola are x=t^2+1, y=2t+1. The Cartesian equation of its directrix is a. x=0 b. x+1=0 c. y=0 d. none of these

The equation of the directrix of the parabola y^2+4y+4x+2=0 is (a) x=-1 (b) x=1 x=-3/2 (d) x=3/2

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

A plane through the line (x-1)/1=(y+1)/(-2)=z/1 has the equation (A) x+y+z=0 (B) 3x+2y-z=1 (C) 4x+y-2z=3 (D) 3x+2y+z=0

The inverse of the point (1, 2) with respect to the circle x^(2) + y^(2) - 4x - 6y + 9 = 0 is

The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^2+y^2-2x-4y+1=0a n dx^2+y^2-4x-2y+4=0 is

Equation of normal to the parabola y^(2)=4x which passes through (3, 0), is