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If a,b,c form a GP with common ratio r, ...

If a,b,c form a GP with common ratio r, the sum of the ordinates of the points of intersection of the line ax+by+c=0 and the curve `x+2y^2=0` is

A

a) `(-r^(2))/(2)`

B

b) `-(r)/(2)`

C

c)`(r)/(2)`

D

d) r

Text Solution

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The correct Answer is:
To solve the problem, we need to find the sum of the ordinates of the points of intersection of the line \( ax + by + c = 0 \) and the curve \( x + 2y^2 = 0 \), given that \( a, b, c \) are in geometric progression (GP) with common ratio \( r \). ### Step-by-Step Solution: 1. **Identify the equations**: The line is given by: \[ ax + by + c = 0 \quad \text{(Equation 1)} \] The curve is given by: \[ x + 2y^2 = 0 \quad \text{(Equation 2)} \] 2. **Express \( b \) and \( c \) in terms of \( a \)**: Since \( a, b, c \) are in GP with common ratio \( r \), we can express: \[ b = ar \quad \text{and} \quad c = ar^2 \] 3. **Substitute \( b \) and \( c \) into the line equation**: Substituting these values into Equation 1 gives: \[ ax + ar y + ar^2 = 0 \] Factoring out \( a \) (assuming \( a \neq 0 \)): \[ a(x + ry + r^2) = 0 \implies x + ry + r^2 = 0 \] Thus, we have: \[ x = -ry - r^2 \quad \text{(Equation 3)} \] 4. **Substitute \( x \) from Equation 3 into Equation 2**: Substitute \( x \) into the curve equation: \[ -ry - r^2 + 2y^2 = 0 \] Rearranging gives: \[ 2y^2 - ry - r^2 = 0 \] 5. **Solve the quadratic equation for \( y \)**: Using the quadratic formula \( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \): Here, \( A = 2 \), \( B = -r \), and \( C = -r^2 \): \[ y = \frac{-(-r) \pm \sqrt{(-r)^2 - 4 \cdot 2 \cdot (-r^2)}}{2 \cdot 2} \] Simplifying this: \[ y = \frac{r \pm \sqrt{r^2 + 8r^2}}{4} = \frac{r \pm \sqrt{9r^2}}{4} = \frac{r \pm 3r}{4} \] 6. **Calculate the two values of \( y \)**: The two solutions for \( y \) are: \[ y_1 = \frac{4r}{4} = r \quad \text{and} \quad y_2 = \frac{-2r}{4} = -\frac{r}{2} \] 7. **Find the sum of the ordinates**: The sum of the ordinates (the \( y \)-values) is: \[ y_1 + y_2 = r - \frac{r}{2} = \frac{2r}{2} - \frac{r}{2} = \frac{r}{2} \] ### Final Answer: The sum of the ordinates of the points of intersection is: \[ \frac{r}{2} \]
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