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On the parabola = y^(2)=8x. If one extri...

On the parabola = `y^(2)=8x`. If one extrimity of focal chord is `((1)/(2),-2)` then its other extrimity is

A

`(8,(1)/(2))`

B

`((1)/(8), -8)`

C

`(2,2)`

D

(8,8)

Text Solution

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The correct Answer is:
To find the other extremity of the focal chord of the parabola \( y^2 = 8x \) given one extremity at \( \left(\frac{1}{2}, -2\right) \), we can follow these steps: ### Step 1: Identify the parameters of the parabola The given parabola is \( y^2 = 8x \). We can compare this with the standard form \( y^2 = 4ax \) to identify \( a \): \[ 4a = 8 \implies a = 2 \] **Hint:** Remember that in the standard form of a parabola, \( y^2 = 4ax \), \( a \) represents the distance from the vertex to the focus. ### Step 2: Determine the coordinates of the given point The coordinates of the given extremity of the focal chord are: \[ P\left(\frac{1}{2}, -2\right) \] Here, \( x = \frac{1}{2} \) and \( y = -2 \). **Hint:** Make sure to note down the coordinates clearly as they will be used to find the parameter \( t_1 \). ### Step 3: Find the parameter \( t_1 \) For the parabola, the coordinates of any point can be expressed in terms of the parameter \( t \) as: \[ (x, y) = (at^2, 2at) \] Substituting \( a = 2 \): \[ (x, y) = (2t^2, 4t) \] From the point \( P\left(\frac{1}{2}, -2\right) \), we have: \[ 4t_1 = -2 \implies t_1 = -\frac{1}{2} \] **Hint:** Use the \( y \)-coordinate to find the value of \( t_1 \) since it relates directly to the parameterization of the parabola. ### Step 4: Find the parameter \( t_2 \) for the other extremity The relationship between the parameters of the endpoints of a focal chord is given by: \[ t_1 \cdot t_2 = -1 \] Substituting \( t_1 = -\frac{1}{2} \): \[ -\frac{1}{2} \cdot t_2 = -1 \implies t_2 = 2 \] **Hint:** Remember that the product of the parameters of the endpoints of a focal chord is always \(-1\). ### Step 5: Calculate the coordinates of the other extremity \( Q \) Using \( t_2 = 2 \) in the parameterization: \[ Q = (2t_2^2, 4t_2) = (2 \cdot 2^2, 4 \cdot 2) = (2 \cdot 4, 8) = (8, 8) \] **Hint:** Substitute \( t_2 \) into the parameterization formula to find the coordinates of the other extremity of the focal chord. ### Conclusion Thus, the coordinates of the other extremity of the focal chord are: \[ \boxed{(8, 8)} \]
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