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If the focus is (1,-1) and the directrix...

If the focus is (1,-1) and the directrix is the line x+2y-9=0, the vertex of the parabola is

A

(1,2)

B

(2,1)

C

(1,-2)

D

(2,-1)

Text Solution

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The correct Answer is:
To find the vertex of the parabola given the focus and the directrix, we can follow these steps: ### Step 1: Identify the Focus and Directrix The focus of the parabola is given as \( S(1, -1) \) and the directrix is the line \( x + 2y - 9 = 0 \). ### Step 2: Find the Slope of the Directrix The equation of the directrix can be rewritten in slope-intercept form: \[ 2y = -x + 9 \implies y = -\frac{1}{2}x + \frac{9}{2} \] From this, we can see that the slope \( m_1 \) of the directrix is \( -\frac{1}{2} \). ### Step 3: Determine the Slope of the Axis of the Parabola The slope of the axis of the parabola is the negative reciprocal of the slope of the directrix. Therefore: \[ m_2 = -\frac{1}{m_1} = -\frac{1}{-\frac{1}{2}} = 2 \] ### Step 4: Write the Equation of the Axis Using the point-slope form of the line, we can write the equation of the axis which passes through the focus \( S(1, -1) \): \[ y - (-1) = 2(x - 1) \] This simplifies to: \[ y + 1 = 2x - 2 \implies 2x - y - 3 = 0 \] ### Step 5: Find the Intersection Point of the Directrix and the Axis To find the intersection point \( P \) of the directrix and the axis, we need to solve the two equations: 1. Directrix: \( x + 2y - 9 = 0 \) 2. Axis: \( 2x - y - 3 = 0 \) From the second equation, we can express \( y \) in terms of \( x \): \[ y = 2x - 3 \] Substituting this into the directrix equation: \[ x + 2(2x - 3) - 9 = 0 \] This expands to: \[ x + 4x - 6 - 9 = 0 \implies 5x - 15 = 0 \implies x = 3 \] Now substituting \( x = 3 \) back to find \( y \): \[ y = 2(3) - 3 = 6 - 3 = 3 \] Thus, the coordinates of point \( P \) are \( (3, 3) \). ### Step 6: Find the Vertex \( Q \) The vertex \( Q \) is the midpoint between the focus \( S(1, -1) \) and the intersection point \( P(3, 3) \). Using the midpoint formula: \[ Q = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{1 + 3}{2}, \frac{-1 + 3}{2} \right) = \left( \frac{4}{2}, \frac{2}{2} \right) = (2, 1) \] ### Final Answer The vertex of the parabola is \( Q(2, 1) \). ---
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