Home
Class 12
MATHS
The point of contact of 9x+8y-11=0 to th...

The point of contact of 9x+8y-11=0 to the hyperbola `3x^(2)-4y^(2)=11` is

A

(3,-2)

B

(3,2)

C

(-3,-3)

D

(3,3)

Text Solution

AI Generated Solution

The correct Answer is:
To find the point of contact of the line \(9x + 8y - 11 = 0\) with the hyperbola \(3x^2 - 4y^2 = 11\), we can follow these steps: ### Step 1: Write down the equations The equations we have are: 1. Hyperbola: \(3x^2 - 4y^2 = 11\) (Equation 1) 2. Line: \(9x + 8y - 11 = 0\) (Equation 2) ### Step 2: Solve the line equation for \(y\) From Equation 2, we can express \(y\) in terms of \(x\): \[ 8y = 11 - 9x \implies y = \frac{11 - 9x}{8} \] Let this be Equation 3. ### Step 3: Substitute \(y\) in the hyperbola equation Now, substitute Equation 3 into Equation 1: \[ 3x^2 - 4\left(\frac{11 - 9x}{8}\right)^2 = 11 \] ### Step 4: Simplify the equation First, calculate \(\left(\frac{11 - 9x}{8}\right)^2\): \[ \left(\frac{11 - 9x}{8}\right)^2 = \frac{(11 - 9x)^2}{64} = \frac{121 - 198x + 81x^2}{64} \] Now substitute this back into the hyperbola equation: \[ 3x^2 - 4\left(\frac{121 - 198x + 81x^2}{64}\right) = 11 \] Multiply through by 64 to eliminate the fraction: \[ 192x^2 - 4(121 - 198x + 81x^2) = 704 \] Expanding gives: \[ 192x^2 - 484 + 792x - 324x^2 = 704 \] Combine like terms: \[ (192 - 324)x^2 + 792x - 484 - 704 = 0 \] This simplifies to: \[ -132x^2 + 792x - 1188 = 0 \] Dividing the entire equation by -12: \[ 11x^2 - 66x + 99 = 0 \] ### Step 5: Solve the quadratic equation Now we can solve this quadratic equation using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\): Here, \(a = 11\), \(b = -66\), and \(c = 99\): \[ x = \frac{66 \pm \sqrt{(-66)^2 - 4 \cdot 11 \cdot 99}}{2 \cdot 11} \] Calculating the discriminant: \[ (-66)^2 - 4 \cdot 11 \cdot 99 = 4356 - 4356 = 0 \] Since the discriminant is 0, there is one real solution: \[ x = \frac{66}{22} = 3 \] ### Step 6: Find \(y\) using the value of \(x\) Substituting \(x = 3\) back into Equation 3 to find \(y\): \[ y = \frac{11 - 9 \cdot 3}{8} = \frac{11 - 27}{8} = \frac{-16}{8} = -2 \] ### Step 7: Conclusion The point of contact is: \[ (3, -2) \]
Promotional Banner

Similar Questions

Explore conceptually related problems

The point of contact of 5x+6y+1=0 to the hyperbola 2x^(2)-3y^(2)=2 is

The mid point of the chord x+2y+3=0 of the hyperbola x^(2)-y^(2)=4 is

The equation of the chord of contact of tangents from (1,2) to the hyperbola 3x^(2)-4y^(2)=3 , is

The point of contact 8x-9y+5 = 0 with the ellipse 4x^(2)+9y^(2)=1 is

The mid-point of the chord intercepted by the hyperbola 9x^(2)-16y^(2)=144 on the line 9x-8y-10=0 , is

If x= 9 is a chord of contact of the hyperbola x^(2) -y^(2) =9 , then the equation of the tangents at one of the points of contact is

The equation of the tangent to the hyperbola 3x^(2) - 8y^(2) = 24 and perpendicular to the line 3x -2y = 4 is

The equation of directrices of the hyperbola 5x^(2) -4y^(2) -30x -8y -39 =0 are

If x=9 is the chord of contact of the hyperbola x^2-y^2=9 then the equation of the corresponding pair of tangents is (A) 9x^2-8y^2+18x-9=0 (B) 9x^2-8y^2-18x+9=0 (C) 9x^2-8y^2-18x-9=0 (D) 9x^2-8y^2+18x+9=0

If x=9 is the chord of contact of the hyperbola x^2-y^2=9 then the equation of the corresponding pair of tangents is (A) 9x^2-8y^2+18x-9=0 (B) 9x^2-8y^2-18x+9=0 (C) 9x^2-8y^2-18x-9=0 (D) 9x^2-8y^2+18x+9=0