Find the equation of the normal to the h...

Find the equation of the normal to the hyperbola `x^(2)-3y^(2)=144` at the positive end of the latus rectum.

A

`sqrt3x +2y=32`

B

`sqrt3x- 3y=48`

C

`3x+sqrt3y=48`

D

`3x-sqrt3y=48`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

Find the equations of the tangent and normal to the parabola y^(2) =6x at the positive end of the latus rectum

Find the equation of normal to the hyperbola 3x^2-y^2=1 having slope 1/3

Find the equation of the normal at theta=(pi)/(3) to the hyperbola 3x^(2)-4y^(2)=12 .

Find the equations of normal to the parabola y^2=4a x at the ends of the latus rectum.

Find the equation of normal at point (4, 3) for the hyperbola 3x^(2) - 4y^(2) = 14 .

The length of the latus rectum of the hyperbola x^(2) -4y^(2) =4 is

The equation of the tangent to the parabola y^(2)=4x at the end of the latus rectum in the fourth quadrant is

Find the latus-rectum of the hyperbola x^2−4y^2=4