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The line x+y+1=0 is an asymptote of x^(2...

The line x+y+1=0 is an asymptote of `x^(2)-y^(2)+x-y-2=0`. The other asymptote is

A

a) x+y=0

B

b) x-y=0

C

c) x-y=1

D

d) x-y+1=0

Text Solution

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The correct Answer is:
To find the other asymptote of the hyperbola defined by the equation \(x^2 - y^2 + x - y - 2 = 0\), given that one asymptote is \(x + y + 1 = 0\), we can follow these steps: ### Step 1: Rearrange the hyperbola equation We start with the equation of the hyperbola: \[ x^2 - y^2 + x - y - 2 = 0 \] Rearranging gives: \[ x^2 + x - y^2 - y - 2 = 0 \] ### Step 2: Complete the square We will complete the square for both \(x\) and \(y\). For \(x^2 + x\): \[ x^2 + x = (x + \frac{1}{2})^2 - \frac{1}{4} \] For \(-y^2 - y\): \[ -y^2 - y = -\left(y^2 + y\right) = -\left((y + \frac{1}{2})^2 - \frac{1}{4}\right) = - (y + \frac{1}{2})^2 + \frac{1}{4} \] Substituting these back into the equation: \[ \left(x + \frac{1}{2}\right)^2 - \frac{1}{4} - \left(y + \frac{1}{2}\right)^2 + \frac{1}{4} - 2 = 0 \] This simplifies to: \[ \left(x + \frac{1}{2}\right)^2 - \left(y + \frac{1}{2}\right)^2 - 2 = 0 \] ### Step 3: Rearranging to standard form Rearranging gives: \[ \left(x + \frac{1}{2}\right)^2 - \left(y + \frac{1}{2}\right)^2 = 2 \] Dividing through by 2: \[ \frac{\left(x + \frac{1}{2}\right)^2}{2} - \frac{\left(y + \frac{1}{2}\right)^2}{2} = 1 \] ### Step 4: Identify the center and slopes of the asymptotes The center of the hyperbola is at \((-1/2, -1/2)\). The slopes of the asymptotes for a hyperbola of the form \(\frac{(x - h)^2}{a^2} - \frac{(y - k)^2}{b^2} = 1\) are given by: \[ y - k = \pm \frac{b}{a}(x - h) \] In our case, since \(a^2 = 2\) and \(b^2 = 2\), the slopes are: \[ \pm 1 \] ### Step 5: Write the equations of the asymptotes The first asymptote is given as \(x + y + 1 = 0\) (which has a slope of -1). The second asymptote, with a slope of 1, can be written as: \[ y + \frac{1}{2} = 1\left(x + \frac{1}{2}\right) \] This simplifies to: \[ y = x \] ### Step 6: Final form of the other asymptote Thus, the equation of the other asymptote is: \[ x - y = 0 \] ### Conclusion The other asymptote is \(x - y = 0\).
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