(i) Find the equation of the Hyperbola with its transverse axis parallel to x-axis and its centre is (3, 2) and length of axes are 8,6.
(ii) Obtain the equation to the hyperbola whose foci are (4, 2) and (8.2) and e=2
(iii) Obtain the equation to the hyperbola in the Standard form whose Focus (6.0) centre (1,0) and the length of transverse axis is 6.

Options

A. `((x-3)^(2))/(16)-((y+2)^(2))/(9)=1`
B. `((x+2)^(2))/(25)-((y-1)^(2))/(11)=1`
C. `((x-3)^(2))/(6)-((y-2)^(2))/(9)=-1`
D. `((x-2)^(2))/(16)-((y-3)^(2))/(19)=1`

Answer

A