Home
Class 12
MATHS
Assertion (A): The locus of the point ((...

Assertion (A): The locus of the point `((e^(2t)+e^(-2t))/(2), (e^(2t)-e^(-2t))/(2))` when 't' is a parameter represents a rectangular hyperbola.
Reason (R ) : The eccentricity of a rectangular hyperbola is 2.

A

a) Both A and R are true and R is the correct explanation of A

B

b) Both A and R are true and R is not the correct explanation of A

C

c) A is true, R is false

D

d) A is false, R is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the assertion and the reason given in the question. ### Step 1: Identify the point representation The point given is: \[ P\left(x, y\right) = \left(\frac{e^{2t} + e^{-2t}}{2}, \frac{e^{2t} - e^{-2t}}{2}\right) \] We will denote: \[ x = \frac{e^{2t} + e^{-2t}}{2} \] \[ y = \frac{e^{2t} - e^{-2t}}{2} \] ### Step 2: Express \(e^{2t}\) and \(e^{-2t}\) in terms of \(x\) and \(y\) From the expressions for \(x\) and \(y\), we can express \(e^{2t}\) and \(e^{-2t}\): 1. Adding the equations: \[ x + y = \frac{e^{2t} + e^{-2t}}{2} + \frac{e^{2t} - e^{-2t}}{2} = e^{2t} \] Thus, \(e^{2t} = x + y\). 2. Subtracting the equations: \[ x - y = \frac{e^{2t} + e^{-2t}}{2} - \frac{e^{2t} - e^{-2t}}{2} = e^{-2t} \] Thus, \(e^{-2t} = x - y\). ### Step 3: Formulate the equation Now, we can express: \[ e^{2t} \cdot e^{-2t} = (x + y)(x - y) \] Since \(e^{2t} \cdot e^{-2t} = 1\), we have: \[ (x + y)(x - y) = 1 \] ### Step 4: Rearranging the equation Expanding the left-hand side gives: \[ x^2 - y^2 = 1 \] This is the standard form of a hyperbola. ### Step 5: Identify the type of hyperbola The equation \(x^2 - y^2 = 1\) represents a rectangular hyperbola, which is characterized by the property that the transverse and conjugate axes are equal in length. ### Step 6: Analyze the eccentricity The eccentricity \(e\) of a rectangular hyperbola is given by: \[ e = \sqrt{1 + \frac{b^2}{a^2}} = \sqrt{1 + 1} = \sqrt{2} \] Thus, the eccentricity of a rectangular hyperbola is \(\sqrt{2}\), not 2. ### Conclusion - The assertion (A) is **true**: The locus represents a rectangular hyperbola. - The reason (R) is **false**: The eccentricity of a rectangular hyperbola is \(\sqrt{2}\), not 2. Thus, the correct answer is that assertion (A) is true, but reason (R) is false.
Promotional Banner

Similar Questions

Explore conceptually related problems

The locus of the point ( (e^(t) +e^(-t))/( 2),(e^t-e^(-t))/(2)) is a hyperbola of eccentricity

Prove that the eccentricity of a rectangular hyperbola is equal to sqrt2 .

If x=(e^(t)+e^(-t))/(2),y=(e^(t)-e^(-t))/(2)," then: "(dy)/(dx)=

Find the locus of the point (t^2-t+1,t^2+t+1),t in Rdot

Find the locus of the point (t^2-t+1,t^2+t+1),t in R .

Find (dy)/(dx), when x=(e^t+e^(-t))/2 \ a n d \ y=(e^t-e^(-t))/2

Find the value of ln(int_(0)^(1) e^(t^(2)+t)(2t^(2)+t+1)dt)

The locus of a point represent by x=(a)/(2)((t+1)/(t)),y=(a)/(2)((t-1)/(t)) , where t=in R-{0} , is

Evaluate int_(-oo)^(0)(te^(t))/(sqrt(1-e^(2t)))dt

The locus of the moving point whose coordinates are given by (e^t+e^(-t),e^t-e^(-t)) where t is a parameter, is x y=1 (b) x+y=2 x^2-y^2=4 (d) x^2-y^2=2