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The area bounded by the curve y=f(x) the...

The area bounded by the curve `y=f(x)` the coordinate axes and the line x = t is given by `te^(t)` then f(x) =

A

`e^(x)(x+1)`

B

`e^(x)(x-1)`

C

`x(1+e^(x))`

D

`x(1-e^(x))`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the function \( f(x) \) given that the area bounded by the curve \( y = f(x) \), the coordinate axes, and the line \( x = t \) is equal to \( t e^t \). ### Step-by-Step Solution: 1. **Understanding the Area**: The area \( A \) bounded by the curve \( y = f(x) \), the x-axis, and the line \( x = t \) can be expressed as: \[ A = \int_0^t f(x) \, dx \] According to the problem, this area is given to be: \[ A = t e^t \] 2. **Setting Up the Equation**: We can set up the equation: \[ \int_0^t f(x) \, dx = t e^t \] 3. **Differentiating Both Sides**: To find \( f(t) \), we differentiate both sides with respect to \( t \): \[ \frac{d}{dt} \left( \int_0^t f(x) \, dx \right) = \frac{d}{dt} (t e^t) \] By the Fundamental Theorem of Calculus, the left side simplifies to: \[ f(t) - f(0) \] The right side can be differentiated using the product rule: \[ \frac{d}{dt} (t e^t) = e^t + t e^t \] Therefore, we have: \[ f(t) - f(0) = e^t + t e^t \] 4. **Assuming \( f(0) = 0 \)**: Since \( f(0) \) represents the value of the function at \( x = 0 \), we can assume \( f(0) = 0 \) (as it is a common assumption in such problems). Thus, we have: \[ f(t) = e^t + t e^t \] 5. **Factoring the Expression**: We can factor out \( e^t \): \[ f(t) = e^t (1 + t) \] 6. **Final Expression**: Since \( t \) is a dummy variable, we can replace \( t \) with \( x \) to express \( f(x) \): \[ f(x) = e^x (1 + x) \] ### Conclusion: The function \( f(x) \) is given by: \[ f(x) = e^x (1 + x) \]
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