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The area bounded by y=1-|x| and X-axis i...

The area bounded by `y=1-|x|` and X-axis is

A

1

B

2

C

`(1)/(2)`

D

`(3)/(4)`

Text Solution

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The correct Answer is:
To find the area bounded by the curve \( y = 1 - |x| \) and the x-axis, we can follow these steps: ### Step 1: Understand the function The function \( y = 1 - |x| \) can be split into two cases based on the definition of the absolute value: - For \( x \geq 0 \): \( y = 1 - x \) - For \( x < 0 \): \( y = 1 + x \) ### Step 2: Find the points of intersection with the x-axis To find the area, we first need to determine where the curve intersects the x-axis. This occurs when \( y = 0 \). 1. For \( x \geq 0 \): \[ 1 - x = 0 \implies x = 1 \] So, the point of intersection is \( (1, 0) \). 2. For \( x < 0 \): \[ 1 + x = 0 \implies x = -1 \] So, the point of intersection is \( (-1, 0) \). ### Step 3: Sketch the graph The graph of the function consists of two linear segments: - From \( (-1, 0) \) to \( (0, 1) \) (where \( y = 1 + x \)) - From \( (0, 1) \) to \( (1, 0) \) (where \( y = 1 - x \)) ### Step 4: Calculate the area The area bounded by the curve and the x-axis can be calculated as the area of the triangle formed by the points \( (-1, 0) \), \( (1, 0) \), and \( (0, 1) \). The base of the triangle is the distance between \( (-1, 0) \) and \( (1, 0) \), which is: \[ \text{Base} = 1 - (-1) = 2 \] The height of the triangle is the y-coordinate of the vertex at \( (0, 1) \), which is: \[ \text{Height} = 1 \] The area \( A \) of the triangle is given by: \[ A = \frac{1}{2} \times \text{Base} \times \text{Height} = \frac{1}{2} \times 2 \times 1 = 1 \] ### Conclusion The area bounded by the curve \( y = 1 - |x| \) and the x-axis is \( 1 \) square unit. ---
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