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The coefficient of x^53 in sum(r = 0)^(1...

The coefficient of `x^53` in `sum_(r = 0)^(100) ""^100C_r (x - 3)^(100 - r) .2^r` is

A

`""^100C_47`

B

`""^100C_53`

C

`""^(-100)C_53`

D

`""^100C_100`

Text Solution

AI Generated Solution

The correct Answer is:
To find the coefficient of \( x^{53} \) in the expression \[ \sum_{r=0}^{100} \binom{100}{r} (x - 3)^{100 - r} \cdot 2^r, \] we can simplify the expression using the Binomial Theorem. ### Step-by-Step Solution: 1. **Recognize the Binomial Expansion**: The given sum can be rewritten as the expansion of \( (x - 3 + 2)^{100} \) using the Binomial Theorem. This is because: \[ (x - 3 + 2)^{100} = (x - 1)^{100}. \] 2. **Apply the Binomial Theorem**: According to the Binomial Theorem, we can expand \( (x - 1)^{100} \): \[ (x - 1)^{100} = \sum_{k=0}^{100} \binom{100}{k} x^{100-k} (-1)^k. \] 3. **Identify the Required Coefficient**: We need to find the coefficient of \( x^{53} \) in this expansion. The term corresponding to \( x^{53} \) will occur when \( 100 - k = 53 \), which implies: \[ k = 100 - 53 = 47. \] 4. **Calculate the Coefficient**: The coefficient of \( x^{53} \) is given by: \[ \binom{100}{47} (-1)^{47}. \] 5. **Simplify the Expression**: Since \( (-1)^{47} = -1 \), the coefficient simplifies to: \[ -\binom{100}{47}. \] Thus, the coefficient of \( x^{53} \) in the given expression is \[ -\binom{100}{47}. \] ### Final Answer: The coefficient of \( x^{53} \) is \( -\binom{100}{47} \). ---
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