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Find 14C1 +14 C2 + 14 C3 +….. + 14 C14= ...

Find `14C_1 +14 C_2 + 14 C_3 +….. + 14 C_14=` ?

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To solve the problem of finding the sum \( 14C_1 + 14C_2 + 14C_3 + \ldots + 14C_{14} \), we can use a property of binomial coefficients. Here’s a step-by-step solution: ### Step 1: Understand the Binomial Coefficient Sum The sum of the binomial coefficients from \( nC_0 \) to \( nC_n \) is given by the formula: \[ \sum_{k=0}^{n} nC_k = 2^n \] This means that the total sum of all binomial coefficients for a given \( n \) equals \( 2^n \). ### Step 2: Apply the Formula In our case, we want to find the sum from \( 14C_1 \) to \( 14C_{14} \). Notice that: \[ \sum_{k=0}^{14} 14C_k = 2^{14} \] This includes \( 14C_0 \) as well, which is equal to 1. Therefore, we can express our desired sum as: \[ 14C_1 + 14C_2 + 14C_3 + \ldots + 14C_{14} = \sum_{k=0}^{14} 14C_k - 14C_0 \] ### Step 3: Calculate \( 2^{14} \) Now, we calculate \( 2^{14} \): \[ 2^{14} = 16384 \] ### Step 4: Subtract \( 14C_0 \) Since \( 14C_0 = 1 \), we subtract this from the total: \[ 14C_1 + 14C_2 + 14C_3 + \ldots + 14C_{14} = 16384 - 1 = 16383 \] ### Final Answer Thus, the final answer is: \[ \boxed{16383} \]
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