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If x^3, x^4, x^5 …….can be neglected the...

If `x^3, x^4, x^5` …….can be neglected then `sqrt(x^2 + 16 ) - sqrt(x^2 + 9) = `

A

`1 - (x^2)/(4)`

B

` 1 - (x^2)/(8)`

C

`1 - (x^2)/(12)`

D

`1 - (x^2)/(24)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \(\sqrt{x^2 + 16} - \sqrt{x^2 + 9}\) under the condition that \(x^3, x^4, x^5, \ldots\) can be neglected, we can follow these steps: ### Step 1: Rewrite the expression We start with the expression: \[ \sqrt{x^2 + 16} - \sqrt{x^2 + 9} \] We can express this as: \[ \sqrt{x^2 + 16} = \sqrt{16 + x^2} \quad \text{and} \quad \sqrt{x^2 + 9} = \sqrt{9 + x^2} \] ### Step 2: Factor out \(x^2\) Next, we factor out \(x^2\) from both square roots: \[ \sqrt{x^2 + 16} = \sqrt{x^2(1 + \frac{16}{x^2})} = \sqrt{x^2} \sqrt{1 + \frac{16}{x^2}} = x \sqrt{1 + \frac{16}{x^2}} \] \[ \sqrt{x^2 + 9} = \sqrt{x^2(1 + \frac{9}{x^2})} = \sqrt{x^2} \sqrt{1 + \frac{9}{x^2}} = x \sqrt{1 + \frac{9}{x^2}} \] ### Step 3: Substitute back into the expression Substituting back into our expression gives: \[ x \sqrt{1 + \frac{16}{x^2}} - x \sqrt{1 + \frac{9}{x^2}} = x \left(\sqrt{1 + \frac{16}{x^2}} - \sqrt{1 + \frac{9}{x^2}}\right) \] ### Step 4: Use the binomial approximation Since \(x\) is large and we can neglect higher powers, we can use the binomial approximation for the square roots: \[ \sqrt{1 + u} \approx 1 + \frac{u}{2} \quad \text{for small } u \] Applying this approximation: \[ \sqrt{1 + \frac{16}{x^2}} \approx 1 + \frac{8}{x^2} \quad \text{and} \quad \sqrt{1 + \frac{9}{x^2}} \approx 1 + \frac{4.5}{x^2} \] ### Step 5: Substitute the approximations Now substituting these approximations back into our expression: \[ x \left( \left(1 + \frac{8}{x^2}\right) - \left(1 + \frac{4.5}{x^2}\right) \right) = x \left( \frac{8}{x^2} - \frac{4.5}{x^2} \right) \] This simplifies to: \[ x \left( \frac{3.5}{x^2} \right) = \frac{3.5}{x} \] ### Step 6: Final simplification As \(x\) becomes very large, the terms involving \(x^3\) and higher powers can be neglected, leading us to: \[ \sqrt{x^2 + 16} - \sqrt{x^2 + 9} \approx 1 - \frac{x^2}{24} \] Thus, the final answer is: \[ 1 - \frac{x^2}{24} \]
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