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Assertion (A) : In the (1+x)^50, the sum...

Assertion (A) : In the `(1+x)^50`, the sum of the coefficients of odd powers of x is `2^49`
Reason ( R) : The sum of coefficients of odd powers of x in `(1+x)^n` is `2^(n-1)`

A

A and R are true , R is correct explanation of A

B

A and R are true, R is not the correct explanation of A

C

A is true , R is false

D

A is false R is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the assertion and the reason given in the question regarding the binomial expansion of \((1+x)^{50}\). ### Step-by-Step Solution: 1. **Understanding the Binomial Expansion**: The binomial expansion of \((1+x)^{50}\) is given by: \[ (1+x)^{50} = \sum_{k=0}^{50} \binom{50}{k} x^k \] Here, \(\binom{50}{k}\) represents the coefficients of the expansion. 2. **Identifying Coefficients of Odd Powers**: The coefficients of odd powers of \(x\) in the expansion are \(\binom{50}{1}, \binom{50}{3}, \binom{50}{5}, \ldots, \binom{50}{49}\). 3. **Finding the Total Sum of Coefficients**: To find the sum of the coefficients of odd powers, we can evaluate the expression at \(x=1\): \[ (1+1)^{50} = 2^{50} \] This represents the sum of all coefficients (both odd and even). 4. **Separating Odd and Even Coefficients**: Let \(S\) be the sum of the coefficients of odd powers and \(E\) be the sum of the coefficients of even powers. We have: \[ S + E = 2^{50} \] 5. **Using the Negative Value**: Now, evaluate the expression at \(x=-1\): \[ (1-1)^{50} = 0 \] This gives: \[ S - E = 0 \] Thus, we can conclude that: \[ S = E \] 6. **Solving for S**: From \(S + E = 2^{50}\) and \(S = E\), we can substitute \(E\) with \(S\): \[ S + S = 2^{50} \implies 2S = 2^{50} \implies S = 2^{49} \] Therefore, the sum of the coefficients of odd powers of \(x\) in \((1+x)^{50}\) is indeed \(2^{49}\). 7. **Conclusion**: The assertion (A) is true: The sum of the coefficients of odd powers of \(x\) in \((1+x)^{50}\) is \(2^{49}\). The reason (R) is also true: The sum of coefficients of odd powers of \(x\) in \((1+x)^n\) is \(2^{n-1}\). ### Final Answer: Both assertion (A) and reason (R) are true, and (R) is the correct explanation of (A).
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