Home
Class 12
MATHS
Find the 10th term in the expansion of 5...

Find the 10th term in the expansion of `5^x`

Text Solution

AI Generated Solution

The correct Answer is:
To find the 10th term in the expansion of \(5^x\), we can use the concept of the Taylor series expansion. Here’s a step-by-step solution: ### Step-by-Step Solution: 1. **Understand the Expression**: We start with the expression \(5^x\). We can rewrite this using the exponential function: \[ 5^x = e^{x \log 5} \] 2. **Use the Taylor Series Expansion**: The Taylor series expansion for \(e^y\) around \(y=0\) is given by: \[ e^y = \sum_{n=0}^{\infty} \frac{y^n}{n!} \] In our case, \(y = x \log 5\). Therefore, we can write: \[ e^{x \log 5} = \sum_{n=0}^{\infty} \frac{(x \log 5)^n}{n!} \] 3. **Identify the 10th Term**: The \(n\)-th term in the expansion is given by: \[ T_n = \frac{(x \log 5)^n}{n!} \] For the 10th term, we need to find \(T_9\) (since we start counting from \(n=0\)): \[ T_9 = \frac{(x \log 5)^9}{9!} \] 4. **Final Expression**: Thus, the 10th term in the expansion of \(5^x\) is: \[ T_{10} = \frac{(x \log 5)^9}{9!} \]
Promotional Banner

Similar Questions

Explore conceptually related problems

The 6^(th) term in the expansion of 5^x is

Find the 9th term in the expansion of ( 3x - (1)/( 2x ) )^(8), x ne 0 .

Find the 5th term in the expansion of (1+x^2)^12

Find the 10th term in the binomial expansion of (2x^2+1/x)^(12)dot

Find the 10th term in the binomial expansion of (2x^2+1/x)^(12)dot

Find the (r+1) th term in the expansion of ((x)/(a)-(a)/(x))^(2n)

Find the (r+1) th term in the expansion of ((x)/(a)-(a)/(x))^(2n)

Find the 7th term in the expansion of (3x^2-1/(x^3))^(10)dot

Find the 15th term in the expansion of (2y-(x)/(2))^(18)

Find the 111th term in the expansion of (1+3x)^111.