The area of a triangle inscribed in an ellipse bears a constant ratio to the area of the triangle formed by joining points on the auxiliary circle corresponding to the vertices of the first triangle. This ratio is `b//a` b. `a^2//b^2` c. `2a//b` d. none

Show that the area of triangle inscribed in an ellipse bears a constant ratio to the area of thetriangle formed by joining points on the auxiliary circle corresponding to the vertices of the firsttriangle.

The ratio of any triangle PQR inscribed in an ellipse x^2/a^2+y^2/b^2=1 and that of triangle formed by the corresponding points on the auxilliary circle is b/a .

The ratio of the area of triangle inscribed in ellipse x^2/a^2+y^2/b^2=1 to that of triangle formed by the corresponding points on the auxiliary circle is 0.5. Then, find the eccentricity of the ellipse. (A) 1/2 (B) sqrt3/2 (C) 1/sqrt2 (D) 1/sqrt3

A, B, C are three points on the rectangular hyperbola xy = c^2 , The area of the triangle formed by the points A, B and C is

The area of a triangle with vertices (a,b+c), (b,c+a) and (c,a+b) is

The area of the triangle formed by the tangent at the point (a, b) to the circle x^(2)+y^(2)=r^(2) and the coordinate axes, is

The eccentric angles of the vertices of a triangle inscribed in the ellipse x^2/a^2 + y^2/b^2 =1 are alpha, beta, gamma , then for the area of this triangle to be greatest, the angle subtended by the two consecutive vertices of the triangle at the centre of the ellipse in degree measure is...

In /_\ A B C ,\ /_A=30^@,\ /_B=40^@a n d\ /_C=110^@ . The angles of the triangle formed by joining the mid-points of the sides of this triangle are

Find the area of a triangle formed by the points A(5,\ 2),\ B(4,\ 7)\ a n d\ C(7, 4)dot

Area of the triangle formed by the tangents at the point on the ellipse x^2/a^2+y^2/b^2=1 whose eccentric angles are alpha,beta,gamma is