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The length of the latusrectum 16x^(2)+25...

The length of the latusrectum `16x^(2)+25y^(2) = 400` is

A

`25/2`

B

`25/4`

C

`16/5`

D

`32/5`

Text Solution

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The correct Answer is:
To find the length of the latus rectum of the ellipse given by the equation \( 16x^2 + 25y^2 = 400 \), we can follow these steps: ### Step 1: Rewrite the equation in standard form We start with the equation: \[ 16x^2 + 25y^2 = 400 \] To convert this into the standard form of an ellipse, we divide every term by 400: \[ \frac{16x^2}{400} + \frac{25y^2}{400} = 1 \] This simplifies to: \[ \frac{x^2}{25} + \frac{y^2}{16} = 1 \] ### Step 2: Identify \(a^2\) and \(b^2\) From the standard form \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), we can identify: - \(a^2 = 25\) (since it is under \(x^2\)) - \(b^2 = 16\) (since it is under \(y^2\)) ### Step 3: Determine the values of \(a\) and \(b\) Next, we find \(a\) and \(b\): \[ a = \sqrt{25} = 5 \] \[ b = \sqrt{16} = 4 \] ### Step 4: Use the formula for the length of the latus rectum The formula for the length of the latus rectum \(L\) of an ellipse is given by: \[ L = \frac{2b^2}{a} \] Substituting the values of \(b^2\) and \(a\): \[ L = \frac{2 \times 16}{5} \] ### Step 5: Calculate the length of the latus rectum Now we calculate: \[ L = \frac{32}{5} \] ### Final Answer Thus, the length of the latus rectum is: \[ \frac{32}{5} \]
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