Home
Class 12
MATHS
The equation of the tangent to the ellip...

The equation of the tangent to the ellipse `9x^(2)+16y^(2)=144` at the positive end of the latusrectum is

A

3x+4y=12

B

4x-3y=12

C

`sqrt(7)x+4y=16`

D

`3x+sqrt(7)y=16`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

Find the equation of the normal to the hyperbola x^(2)-3y^(2)=144 at the positive end of the latus rectum.

Find the equations of the tangent and normal to the parabola y^(2) =6x at the positive end of the latus rectum

The equation of the tangent to the hyperbola 16x^(2)-9y^(2)=144 at (5,8//3) , is

Find the length of the latus rectum of the ellipse 9x^(2)+16y^(2)=144

The length of the latusrectum of the ellipse 3x^(2)+y^(2)=12 is

The equation of the tangent to the ellipse x^2+16y^2=16 making an angle of 60^(@) with x-axis is

Find the equations of the tangents to the hyperbla 4x ^(2) - 9y ^(2) = 144, which are perpendicular to the line 6x + 5y = 21.

Find the equation of tangent of the curve 9x^(2)+16y^(2) = 144 at those points at which tangents are parallel to (i) X-axis, (ii) Y-axis.

If x -y+ k = 0 is a tan gen t to the ellip se 9x^(2)+16y^(2)=144 then k =