Home
Class 12
MATHS
The equation of the normal to the ellips...

The equation of the normal to the ellipse `(x^(2))/(4)+(y^(2))/(2)=1` at the point whose eccentric angle is `(pi)/(4)` is

A

`x+sqrt(2)y=2sqrt(2)`

B

`sqrt(2)x-y=1`

C

`x-sqrt(2)y=0`

D

`sqrt(2)x+y=3`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of normal to the ellipse (x^(2))/(16)+(y^(2))/(9) = 1 at the point whose eccentric angle theta=(pi)/(6)

The equation of normal to the ellipse x^(2)+4y^(2)=9 at the point wherr ithe eccentric angle is pi//4 is

The locus of the point of intersection of tangents to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 at the points whose eccentric angles differ by pi//2 , is

The locus of the point of intersection of tangents to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 at the points whose eccentric angles differ by pi//2 , is

If omega is one of the angles between the normals to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 (b>a) at the point whose eccentric angles are theta and pi/2+theta , then prove that (2cotomega)/(sin2theta)=(e^2)/(sqrt(1-e^2))

If omega is one of the angles between the normals to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the point whose eccentric angles are theta and pi/2+theta , then prove that (2cotomega)/(sin2theta)=(e^2)/(sqrt(1-e^2))

The equation of normal to the ellipse 4x^2 +9y^2 = 72 at point (3,2) is:

If the line l x+m y+n=0 cuts the ellipse ((x^2)/(a^2))+((y^2)/(b^2))=1 at points whose eccentric angles differ by pi/2, then find the value of (a^2l^2+b^2m^2)/(n^2) .

Find the equation of the normal to the curve x^2+2y^2-4x-6y+8=0 at the point whose abscissa is 2.

Find the equation of the normal to the curve x^2+2y^2-4x-6y+8=0 at the point whose abscissa is 2.