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The number of tangents to (x^(2))/(25)+(...

The number of tangents to `(x^(2))/(25)+(y^(2))/(9)=1` through (1,1) is

A

0

B

1

C

2

D

3

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of tangents to the ellipse given by the equation \(\frac{x^2}{25} + \frac{y^2}{9} = 1\) through the point (1, 1), we can follow these steps: ### Step 1: Identify the parameters of the ellipse The standard form of the ellipse is given by: \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \] Here, \(a^2 = 25\) and \(b^2 = 9\). Therefore, \(a = 5\) and \(b = 3\). ### Step 2: Set up the equation for tangents We will use the condition for the number of tangents from a point \((h, k)\) to the ellipse. The condition is based on the value of \(S_1\), where: \[ S = \frac{x^2}{25} + \frac{y^2}{9} - 1 \] Substituting the point (1, 1) into this equation gives: \[ S_1 = \frac{1^2}{25} + \frac{1^2}{9} - 1 \] ### Step 3: Calculate \(S_1\) Now, we compute \(S_1\): \[ S_1 = \frac{1}{25} + \frac{1}{9} - 1 \] To combine the fractions, we find a common denominator. The least common multiple of 25 and 9 is 225. Thus: \[ S_1 = \frac{9}{225} + \frac{25}{225} - \frac{225}{225} \] \[ S_1 = \frac{9 + 25 - 225}{225} = \frac{34 - 225}{225} = \frac{-191}{225} \] ### Step 4: Analyze the value of \(S_1\) Since \(S_1 < 0\), we can apply the rule for the number of tangents: - If \(S_1 < 0\), there are 0 tangents. - If \(S_1 = 0\), there is 1 tangent. - If \(S_1 > 0\), there are 2 tangents. ### Conclusion Since \(S_1 < 0\), the number of tangents to the ellipse from the point (1, 1) is: \[ \text{Number of tangents} = 0 \] ### Final Answer The number of tangents to the ellipse through the point (1, 1) is **0**. ---
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