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Equation of line passing through the poi...

Equation of line passing through the points (1,2,3) ,(2,-1,2) is

A

`(x-2)/(2) =(y-2)/(-1) =(z-3)/(2)`

B

`(x-1)/(1)=(y-2)/(-3)=(z-3)/(-1)`

C

`(x-2)/(1)=(y+1)/(2)=(z-1)/(3)`

D

none

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the line passing through the points \( (1, 2, 3) \) and \( (2, -1, 2) \), we can use the symmetric form of the equation of a line in 3D space. Here are the steps to derive the equation: ### Step 1: Identify the Points Let the points be: - \( P_1 = (x_1, y_1, z_1) = (1, 2, 3) \) - \( P_2 = (x_2, y_2, z_2) = (2, -1, 2) \) ### Step 2: Calculate the Direction Ratios The direction ratios of the line can be found by subtracting the coordinates of the two points: - Direction ratios \( (a, b, c) = (x_2 - x_1, y_2 - y_1, z_2 - z_1) \) - Calculate: - \( a = 2 - 1 = 1 \) - \( b = -1 - 2 = -3 \) - \( c = 2 - 3 = -1 \) So, the direction ratios are \( (1, -3, -1) \). ### Step 3: Write the Symmetric Form of the Line The symmetric form of the line passing through the points is given by: \[ \frac{x - x_1}{a} = \frac{y - y_1}{b} = \frac{z - z_1}{c} \] Substituting the values: \[ \frac{x - 1}{1} = \frac{y - 2}{-3} = \frac{z - 3}{-1} \] ### Step 4: Simplify the Equation This can be simplified to: \[ x - 1 = \frac{y - 2}{-3} = \frac{z - 3}{-1} \] Thus, the final symmetric equation of the line is: \[ x - 1 = \frac{y - 2}{-3} = \frac{z - 3}{-1} \] ### Final Answer The equation of the line passing through the points \( (1, 2, 3) \) and \( (2, -1, 2) \) is: \[ \frac{x - 1}{1} = \frac{y - 2}{-3} = \frac{z - 3}{-1} \]
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