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The line x = 1, y = 2 is...

The line x = 1, y = 2 is

A

parallel to the x-axis

B

parallel to the y-axis

C

parallel to the z-axis

D

parallel to the xy-plane

Text Solution

AI Generated Solution

The correct Answer is:
To determine the nature of the line given by the equations \( x = 1 \) and \( y = 2 \), we can follow these steps: ### Step 1: Understand the given equations The equations \( x = 1 \) and \( y = 2 \) indicate that the line is defined at a specific point in the 3D space where \( x \) and \( y \) are constant. **Hint:** Recognize that these equations represent fixed values for \( x \) and \( y \) while \( z \) can take any value. ### Step 2: Rewrite the equations in a standard form We can express the equations in a parametric form. Since \( x \) and \( y \) are constant, we can let \( z \) be a parameter \( t \). Thus, we can write: - \( x = 1 \) - \( y = 2 \) - \( z = t \) **Hint:** Identify the parameter that allows the third dimension to vary freely. ### Step 3: Identify the direction vector From the parametric equations, we can see that the direction vector of the line can be represented as: \[ \vec{d} = (0, 0, 1) \] This indicates that the line moves in the \( z \)-direction only. **Hint:** The direction vector shows how the line extends in space. If only one component is non-zero, it indicates movement along that axis. ### Step 4: Determine the nature of the line Since the line is defined by constant \( x \) and \( y \) values, and \( z \) can vary, this means the line is vertical and parallel to the \( z \)-axis. **Hint:** Consider how the line behaves in relation to the coordinate planes. ### Step 5: Conclusion The line described by \( x = 1 \) and \( y = 2 \) is parallel to the \( z \)-axis and lies in the plane where \( x = 1 \) and \( y = 2 \). Therefore, it does not lie in the \( xy \)-plane but extends vertically. **Final Answer:** The line is parallel to the \( z \)-axis. ---
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