Home
Class 12
MATHS
Equation of a line passing through (1,-2...

Equation of a line passing through (1,-2, 3) and parallel to the plane 2x+3y+z+5 = 0 is

A

`(x-1)/(-1)=(y+2)/(1)=(z-3)/(-1)`

B

`(x-1)/(2)=(y+2)/(3)=(z-3)/(1)`

C

`(x+1)/(-1)=(y-2)/(1)=(z-3)/(-1)`

D

none

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the Vector and Cartesian equation of line passing through (1, -2, 3) and parallel to the planes x - y + 2z = 5 and 3 x + 2y - z = 6

The equation of the line passing through (1, 2, 3) and parallel to the planes x-y + 2z = 5 and 3x + y + z = 6 is.

Equation of plane passing through (2,3,4) and parallel to the plane x+2y+4z=5 is

Equation of a line passing through (-1,2,-3) and perpendicular to the plane 2x+3y+z+5=0 is

Equations of the line passing through (1,1,1) and perpendicular to the plane 2x+3y+z+5=0 are

The equation of line passing through (2, 3, -1) and perpendicular to the plane 2x + y - 5z = 12

Find the equation of a line passing through the point (2,3) and parallel to the line 3x-4y+5=0 .

Write the equation of the plane passing through (2, -1,1) and parallel to the plane 3x+2y-z=7.

Find the equation of a line passing through (1,-1,0) and parallel to the line (x-2)/3=(2y+1)/2=(5-z)/1

Find the equation of plane passing through the point (-1,1,2) and parallel to the plane x + 2y + 3z - 5 = 0.