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The equation of a line through (-2, 3, 4...

The equation of a line through (-2, 3, 4) and parallel to the planes 2x+3y+4z=5 and 3x+4y+5z=6 are

A

`(x-2)/(1)=(y+3)/(3)=(z+4)/(-1)`

B

`(x+2)/(2) =(y-3)/(3)=(z-4)/(1)`

C

`(x+2)/(1)=(y-3)/(-2)=(z-4)/(1)`

D

`(x+2)/(-1)=(y-3)/(-2)=(z-4)/(1)`

Text Solution

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The correct Answer is:
C
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