Atomic weight of silver is 107 .8. Silver crystallises in fee lattice with edge length of unit cell is `4.086 A^0`. Calculate the density of unit cell of silver and radius of silver atom.

Explanation

To solve the problem of calculating the density of the unit cell of silver and the radius of a silver atom, we can follow these steps:

### Step 1: Gather the Given Information
- Atomic weight of silver (Ag) = 107.8 g/mol
- Edge length of the unit cell (a) = 4.086 Å = 4.086 × 10^-10 m

### Step 2: Calculate the Volume of the Unit Cell
The volume (V) of the cubic unit cell can be calculated using the formula:
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