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For the coagulation of 100 ml of arsenio...

For the coagulation of 100 ml of arsenious sulphide solution, 5ml of 1M NaCl is required. Calculated the flocculation value .

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Number of millimoles of electrolyte NaCl required to coagulate 100ml of sol
`= 1 xx 5 = 5`.
Number of millimoles of electrolyte required to coagulate 1000 ml of sol
`=5xx(1000)/(100)=50`.
100 The minimum number of moles of electrolyte per litre required to cause precipitation is called . flocculation value. Flocculating value of NaCl = 50 millimole `L^(-1) = 0.05 mol L^(-1)`
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