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Give the order of coagulating power of C...

Give the order of coagulating power of `Cl, SO_(4)^(2-), PO_(4)^(3-)` in the coagulation of positive sols.

A

`PO_(4)^(3-) gt SO_(4)^(2-) gt Cl^(-)`

B

`SO_(4)^(2-) gt Cl^(-) gt PO_(4)^(3-)`

C

`Cl^(-) gt PO_(4)^(3-) gt SO_(4)^(2-)`

D

`Cl^(-) gt SO_(4)^(2-) gtPO_(4)^(3-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of coagulating power of the ions \( Cl^-, SO_4^{2-}, \) and \( PO_4^{3-} \) in the coagulation of positive sols, we can follow these steps: ### Step 1: Understand Coagulation and Hardy-Schulze Rule Coagulation refers to the process where colloidal particles aggregate to form a larger mass. The Hardy-Schulze rule states that the coagulating power of an ion is related to its valency. Specifically, ions with higher valency have greater coagulating power. ### Step 2: Identify the Valency of Each Ion - \( Cl^- \) has a valency of 1. - \( SO_4^{2-} \) has a valency of 2. - \( PO_4^{3-} \) has a valency of 3. ### Step 3: Compare the Valencies Now, we compare the valencies: - \( PO_4^{3-} \) (valency 3) > \( SO_4^{2-} \) (valency 2) > \( Cl^- \) (valency 1). ### Step 4: Determine the Order of Coagulating Power According to the Hardy-Schulze rule, the order of coagulating power based on the valency is: 1. \( PO_4^{3-} \) (highest coagulating power) 2. \( SO_4^{2-} \) 3. \( Cl^- \) (lowest coagulating power) ### Final Order Thus, the order of coagulating power of the ions in the coagulation of positive sols is: \[ PO_4^{3-} > SO_4^{2-} > Cl^- \]
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