`{:("Substance","Oxidation state of N"),("A) "HNO_(3),"1) "-3","+5),("B) "NH_(4)NO_(3),"2) "-1//3),("C) "N_(3)H,"3) "+5),("D) "H_(3)PO_(3),"d) "+3),(,"5) "+1//3):}`
The correct match is

Options

A. `{:(A,B,C,D),(3,1,2,4):}`
B. `{:(A,B,C,D),(5,2,3,4):}`
C. `{:(A,B,C,D),(1,2,3,4):}`
D. `{:(A,B,C,D),(4,3,2,5):}`

Answer

To find the correct match of substances with their oxidation states of nitrogen, we will analyze each compound step by step.

### Step 1: Analyze HNO₃
1. **Write the equation**:
\[ H + N + 3O = 0 \]
2. **Assign known oxidation states**:
- Hydrogen (H) = +1
- Oxygen (O) = -2
3. **Substitute known values**:
\[ 1 + N + 3(-2) = 0 \]
\[ 1 + N - 6 = 0 \]
4. **Solve for N**:
\[ N - 5 = 0 \implies N = +5 \]

### Step 2: Analyze NH₄NO₃
1. **Break into components**:
- NH₄⁺ and NO₃⁻
2. **For NH₄⁺**:
\[ N + 4(1) = +1 \implies N + 4 = +1 \implies N = -3 \]
3. **For NO₃⁻**:
\[ N + 3(-2) = -1 \implies N - 6 = -1 \implies N = +5 \]

### Step 3: Analyze N₃H
1. **Write the equation**:
\[ 3N + H = 0 \]
2. **Substitute known values**:
\[ 3N + 1 = 0 \]
3. **Solve for N**:
\[ 3N = -1 \implies N = -\frac{1}{3} \]

### Step 4: Analyze H₃PO₃
1. **Write the equation**:
\[ 3(1) + P + 3(-2) = 0 \]
2. **Substitute known values**:
\[ 3 + P - 6 = 0 \]
3. **Solve for P**:
\[ P - 3 = 0 \implies P = +3 \]

### Summary of Results
- **HNO₃**: N = +5
- **NH₄NO₃**: N = -3 (from NH₄⁺)
- **N₃H**: N = -1/3
- **H₃PO₃**: P = +3 (not applicable for N)

### Final Matching
- A) HNO₃: +5
- B) NH₄NO₃: -3
- C) N₃H: -1/3
- D) H₃PO₃: +3 (not relevant for nitrogen)

### Correct Match
- A) HNO₃: +5
- B) NH₄NO₃: -3
- C) N₃H: -1/3
- D) H₃PO₃: +3 (not for N)

The correct matches are:
- A) HNO₃: +5
- B) NH₄NO₃: -3
- C) N₃H: -1/3