Which one of the following statements is correct with respect to basic character ? 

Options

A. `PH_(3) gt P(CH_(3))_(3)`
B. `PH_(3)=NH_(3)`
C. `PH_(3) gt NH_(3)`
D. `P(CH_(3))_(3) gt PH_(3)`

Answer

To determine which statement is correct with respect to the basic character of the compounds mentioned (PS3, NS3, and PH3), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Basicity**: Basicity refers to the ability of a compound to donate a pair of electrons. In the context of the compounds mentioned, we are particularly interested in the lone pairs of electrons present on the central atom (phosphorus or nitrogen).

2. **Comparing Ammonia (NS3) and Phosphine (PS3)**:
- Ammonia (NS3) has a nitrogen atom, while phosphine (PS3) has a phosphorus atom.
- Nitrogen is smaller in size compared to phosphorus, which means that the electron density around nitrogen is higher than that around phosphorus.
- As a result, ammonia (NS3) is more basic than phosphine (PS3) because it can attract protons (H+) more effectively due to its higher electron density.

3. **Analyzing the Options**:
- **Option 1**: PS3 is more basic than PS3 thrice (P(CH3)3). This is incorrect because P(CH3)3 has electron-donating methyl groups that increase its basicity.
- **Option 2**: PS3 is equal to NS3. This is incorrect as we established that NS3 is more basic than PS3.
- **Option 3**: PS3 is greater than NS3. This is also incorrect for the same reason.
- **Option 4**: PS3 thrice (P(CH3)3) is more basic than PS3. This is correct because the presence of three methyl groups increases the electron density around phosphorus, enhancing its ability to donate electrons.

4. **Conclusion**: The correct statement regarding the basic character is that PS3 thrice (P(CH3)3) is more basic than PS3.

### Final Answer:
The correct statement is: PS3 thrice (P(CH3)3) is more basic than PS3.