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Aqueous NaOH reacts with white Phospho r...

Aqueous NaOH reacts with white Phospho rous to form Phosphine and 

A

`NaH_(2)PO_(2)`

B

`P_(2)O_(5)`

C

`Na_(3)PO_(3)`

D

`P_(2)O_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how aqueous NaOH reacts with white phosphorus to form phosphine, we can follow these steps: ### Step 1: Identify the Reactants The reactants in this reaction are: - White phosphorus (P4) - Aqueous sodium hydroxide (NaOH) ### Step 2: Write the Reaction When white phosphorus (P4) reacts with aqueous NaOH, it produces phosphine (PH3) and sodium hypophosphite (NaH2PO2). The reaction can be represented as: \[ P_4 + NaOH \rightarrow PH_3 + NaH_2PO_2 \] ### Step 3: Balance the Reaction To balance the reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation is: \[ P_4 + 4 NaOH \rightarrow 2 PH_3 + 2 NaH_2PO_2 + 2 H_2O \] ### Step 4: Identify the Products From the balanced equation, we can see that the products of the reaction are: - Phosphine (PH3) - Sodium hypophosphite (NaH2PO2) - Water (H2O) ### Conclusion The main products of the reaction between aqueous NaOH and white phosphorus are phosphine (PH3) and sodium hypophosphite (NaH2PO2). ### Final Answer The correct product formed is sodium hypophosphite (NaH2PO2). ---
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