Moles of oxygen that can oxidise one mole of `NH_(3)` to `NO`

Options

A. 1
B. 1.25
C. 2.5
D. 5

Answer

To determine the moles of oxygen that can oxidize one mole of ammonia (NH₃) to nitric oxide (NO), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Reaction**:
The oxidation of ammonia (NH₃) to nitric oxide (NO) involves a reaction with oxygen (O₂). We need to find out how many moles of O₂ are required to oxidize one mole of NH₃.

2. **Identify the Balanced Reaction**:
The balanced reaction for the oxidation of ammonia in the presence of oxygen can be represented as:
\[ 4 \, \text{NH}_3 + 5 \, \text{O}_2 \rightarrow 4 \, \text{NO} + 6 \, \text{H}_2\text{O} \]
This shows that 4 moles of NH₃ react with 5 moles of O₂ to produce 4 moles of NO and 6 moles of water.

3. **Calculate the Moles of O₂ Required for One Mole of NH₃**:
From the balanced equation, we can see that:
- 4 moles of NH₃ require 5 moles of O₂.
- Therefore, for 1 mole of NH₃, the moles of O₂ required can be calculated as:
\[ \text{Moles of O}_2 = \frac{5 \, \text{moles of O}_2}{4 \, \text{moles of NH}_3} \times 1 \, \text{mole of NH}_3 = \frac{5}{4} \, \text{moles of O}_2 \]

4. **Convert to Decimal**:
\[ \frac{5}{4} = 1.25 \]
Thus, 1 mole of NH₃ requires 1.25 moles of O₂ for complete oxidation to NO.

### Final Answer:
The moles of oxygen that can oxidize one mole of NH₃ to NO is **1.25 moles**.

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