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What is the order of basic nature of hyd...

What is the order of basic nature of hydrides of VA group elements?

A

`AsH_(3)gt SbH_(3) gtPH_(3)gt NH_(3)`

B

`NH_(3)> PH_(3) gt AsH_(3) gtSbH_(3)`

C

`NH_(3) gtSbH_(3)gt PH_(3)gt AsH_(3)`

D

`PH_(3) gtNH_(3)gt SbH_(3)gt AsH_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of basic nature of hydrides of VA group elements (Group 15), we will analyze the hydrides: NH₃ (ammonia), PH₃ (phosphine), AsH₃ (arsine), and SbH₃ (stibine). ### Step-by-Step Solution: 1. **Identify the Hydrides**: The hydrides of the VA group elements are NH₃, PH₃, AsH₃, and SbH₃. 2. **Understand Basic Nature**: The basic nature of a hydride is determined by its ability to donate a lone pair of electrons. A stronger base will have a greater tendency to donate its lone pair. 3. **Consider Atomic Size and Electronegativity**: As we move down the group from nitrogen to antimony: - The size of the central atom increases. - The electronegativity of the central atom decreases. 4. **Effect on Lone Pair Donation**: - With an increase in atomic size, the bond length between the central atom and hydrogen increases. This makes the bond weaker and the lone pair less available for donation. - A decrease in electronegativity means that the central atom holds onto its electrons less tightly, but the larger size means that the lone pair is less available for donation. 5. **Order of Basicity**: - NH₃ (ammonia) has the smallest atomic size and highest electronegativity, making it the most basic. - PH₃ (phosphine) is next, as it has a larger size and lower electronegativity than NH₃. - AsH₃ (arsine) follows, with even larger size and lower electronegativity. - SbH₃ (stibine) is the least basic due to the largest size and lowest electronegativity. 6. **Final Order**: Therefore, the order of basic nature of the hydrides is: - NH₃ > PH₃ > AsH₃ > SbH₃ ### Conclusion: The order of basic nature of the hydrides of VA group elements is NH₃ > PH₃ > AsH₃ > SbH₃.
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