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{:("LIST - 1","LIST - 2"),("A) "NH(3),"1...

`{:("LIST - 1","LIST - 2"),("A) "NH_(3),"1) "sp^(3)d", trigonal bipyramidal"),("B) "N_(2)O_(3),"2) "sp^(3)", tetrahedral"),("C) "PCl_(5),"3) sp, linear"),("D) "NH_(4)^(+),"4) "sp^(3)", pyramidal"),(,"5) anhydride of nitrous acid"):}`
The correct match is 

A

`{:(A,B,C,D),(1,4,3,2):}`

B

`{:(A,B,C,D),(1,2,3,4):}`

C

`{:(A,B,C,D),(4,5,1,2):}`

D

`{:(A,B,C,D),(2,5,3,1):}`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the matching question regarding the compounds and their respective hybridizations and shapes, we will analyze each compound step by step. ### Step 1: Analyze NH₃ (Ammonia) - **Structure**: NH₃ has three hydrogen atoms bonded to a nitrogen atom, with one lone pair on nitrogen. - **Hybridization**: The hybridization can be determined by counting the total number of electron pairs (bonds + lone pairs). Here, there are 3 bonds and 1 lone pair, making a total of 4 electron pairs. This corresponds to **sp³ hybridization**. - **Shape**: Due to the presence of the lone pair, the shape is **pyramidal**. ### Step 2: Analyze N₂O₃ (Dinitrogen Trioxide) - **Structure**: N₂O₃ can be considered as the anhydride of nitrous acid (HNO₂). It consists of nitrogen and oxygen atoms. - **Hybridization**: The nitrogen atoms in N₂O₃ are involved in multiple bonds with oxygen. The central nitrogen atom typically exhibits **sp² hybridization** due to the presence of one double bond and one single bond. - **Shape**: The shape around the nitrogen atoms is **bent** due to the presence of lone pairs. ### Step 3: Analyze PCl₅ (Phosphorus Pentachloride) - **Structure**: PCl₅ has five chlorine atoms bonded to a phosphorus atom. - **Hybridization**: The phosphorus atom forms five bonds, leading to **sp³d hybridization**. - **Shape**: The geometry of PCl₅ is **trigonal bipyramidal**. ### Step 4: Analyze NH₄⁺ (Ammonium Ion) - **Structure**: NH₄⁺ consists of four hydrogen atoms bonded to a nitrogen atom, with no lone pairs. - **Hybridization**: There are four bonds and no lone pairs, which corresponds to **sp³ hybridization**. - **Shape**: The shape is **tetrahedral**. ### Summary of Matches - **A) NH₃**: sp³ hybridization, pyramidal shape → **Match with 4** - **B) N₂O₃**: sp² hybridization, bent shape (anhydride of nitrous acid) → **Match with 5** - **C) PCl₅**: sp³d hybridization, trigonal bipyramidal shape → **Match with 1** - **D) NH₄⁺**: sp³ hybridization, tetrahedral shape → **Match with 2** ### Final Matching - A - 4 - B - 5 - C - 1 - D - 2 ### Correct Match: - **A) NH₃ - 4) sp³, pyramidal** - **B) N₂O₃ - 5) anhydride of nitrous acid** - **C) PCl₅ - 1) sp³d, trigonal bipyramidal** - **D) NH₄⁺ - 2) sp³, tetrahedral**
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