If the nitrogen atoms are in a cyclic arrangement in hydrazoic acid, the oxidation states of N are

Options

A. `+3, +3, +3`
B. `0, 0 ,-1`
C. `0, 0, -1//3`
D. `-1//3, -1//3, 0`

Answer

To determine the oxidation states of nitrogen in hydrazoic acid (HN₃) when the nitrogen atoms are in a cyclic arrangement, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Hydrazoic Acid**:
Hydrazoic acid is represented as HN₃. In a cyclic arrangement, we can visualize it as a ring of nitrogen atoms with a hydrogen atom attached. The structure can be depicted as:
```
H - N = N - N
```

2. **Assign Oxidation States**:
- The hydrogen atom (H) typically has an oxidation state of +1.
- The nitrogen atoms need to be analyzed based on their bonding and the overall charge of the molecule.

3. **Analyze the Bonding**:
- In the cyclic structure, we can assume that one nitrogen is double bonded to another nitrogen, and the last nitrogen is single bonded to the first nitrogen.
- The nitrogen atoms can have different oxidation states based on their bonding and the presence of lone pairs.

4. **Determine the Oxidation States**:
- The nitrogen that is double bonded to another nitrogen and has a lone pair will have an oxidation state of 0.
- The nitrogen that is single bonded to the hydrogen will have an oxidation state of +1 due to the bond with hydrogen.
- The nitrogen that is single bonded to the other nitrogen (and has a negative charge) will have an oxidation state of -1.

5. **Summarize the Oxidation States**:
- Therefore, the oxidation states of the nitrogen atoms in the cyclic arrangement of hydrazoic acid are:
- Nitrogen 1: 0
- Nitrogen 2: 0
- Nitrogen 3: -1

6. **Final Answer**:
The oxidation states of nitrogen in hydrazoic acid (HN₃) in a cyclic arrangement are 0, 0, and -1.