Concentrated nitric acid oxidises phosphorous and iodine, respectively to 

Options

A. `H_(3)PO_(3), HI`
B. `H_(3)PO_(3), HIO_(4)`
C. `H_(3)PO_(4), HIO_(3)`
D. `H_(3)PO_(4), HIO_(4)`

Answer

To solve the question of what concentrated nitric acid oxidizes phosphorus and iodine to, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this case are phosphorus (P) and iodine (I2), and the oxidizing agent is concentrated nitric acid (HNO3).

### Step 2: Determine the Products for Phosphorus
When phosphorus is oxidized by concentrated nitric acid, it forms phosphoric acid (H3PO4) along with nitrogen dioxide (NO2) and water (H2O). The balanced chemical equation for this reaction is:

\[ P_4 + 20 HNO_3 \rightarrow 4 H_3PO_4 + 20 NO_2 + 12 H_2O \]

### Step 3: Determine the Products for Iodine
When iodine is oxidized by concentrated nitric acid, it forms iodic acid (HIO3) along with nitrogen dioxide (NO2) and water (H2O). The balanced chemical equation for this reaction is:

\[ I_2 + 10 HNO_3 \rightarrow 2 HIO_3 + 10 NO_2 + 4 H_2O \]

### Step 4: Combine the Results
From the reactions above, we find that:
- Phosphorus is oxidized to phosphoric acid (H3PO4).
- Iodine is oxidized to iodic acid (HIO3).

### Step 5: Write the Final Answer
Thus, the products formed when concentrated nitric acid oxidizes phosphorus and iodine, respectively, are:

**H3PO4 and HIO3.**

### Conclusion
The correct option from the given choices is **H3PO4 and HIO3**.

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