To solve the question "Oxygen and Sulphur have same...", we need to analyze the properties of both elements. Let's go through the steps systematically.
### Step-by-Step Solution:
1. **Identify the Electronic Configuration:**
- Oxygen (O) has the electronic configuration:
\[
1s^2 \, 2s^2 \, 2p^4
\]
- Sulphur (S) has the electronic configuration:
\[
1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^4
\]
2. **Compare the Electronic Configurations:**
- The outer electronic configuration for oxygen is \(2s^2 \, 2p^4\).
- The outer electronic configuration for sulphur is \(3s^2 \, 3p^4\).
- Although both have similar types of orbitals (s and p), they are in different shells, hence their electronic configurations are not the same.
3. **Analyze Atomic Size:**
- Atomic size increases down the group due to the addition of extra electron shells.
- Oxygen has only two electron shells, while sulphur has three electron shells.
- Therefore, sulphur is larger than oxygen, indicating they do not have the same atomic size.
4. **Evaluate Electron Affinity:**
- Electron affinity is the energy change when an electron is added to a neutral atom.
- Generally, smaller atoms have higher electron affinities due to higher charge density.
- However, oxygen has a smaller size and more inter-electronic repulsion due to its higher charge density, which affects its electron affinity.
- Sulphur has a lower electron affinity compared to oxygen because it is larger and has less charge density.
5. **Determine Outer Electronic Configuration:**
- The outer electronic configuration for both elements can be compared:
- Oxygen has \(2s^2 \, 2p^4\) and sulphur has \(3s^2 \, 3p^4\).
- They both have the same type of outer electronic configuration in terms of the number of electrons in the outermost shell.
### Conclusion:
From the analysis, we conclude that the correct statement is that oxygen and sulphur have the same outer electronic configuration.
