Element with the lowest atomicity

Options

A. Te
B. S
C. Se
D. O

Answer

To determine the element with the lowest atomicity from the given options (tellurium, sulfur, selenium, and oxygen), we need to understand the concept of atomicity. Atomicity refers to the total number of atoms present in a molecule of an element.

### Step-by-Step Solution:

1. **Define Atomicity**:
- Atomicity is defined as the number of atoms in a molecule of an element.

2. **Analyze Each Element**:
- **Oxygen (O)**:
- Oxygen exists as O₂ in its molecular form.
- Therefore, the atomicity of oxygen = 2.

- **Tellurium (Te)**:
- Tellurium exists as Te₃ in its molecular form.
- Therefore, the atomicity of tellurium = 3.

- **Sulfur (S)**:
- Sulfur exists as S₈ in its molecular form.
- Therefore, the atomicity of sulfur = 8.

- **Selenium (Se)**:
- Selenium also exists as Se₈ in its molecular form.
- Therefore, the atomicity of selenium = 8.

3. **Compare the Atomicities**:
- Now we compare the atomicities we found:
- Oxygen = 2
- Tellurium = 3
- Sulfur = 8
- Selenium = 8

4. **Identify the Lowest Atomicity**:
- From the comparison, we see that the lowest atomicity is 2, which corresponds to oxygen.

5. **Conclusion**:
- Therefore, the element with the lowest atomicity among the given options is **Oxygen**.

### Final Answer:
The element with the lowest atomicity is **Oxygen (O)**.