The oxidation state of oxygen is zero in

Options

A. `CO`
B. `O_(3)`
C. `SO_(2)`
D. `H_(2)O_(2)`

Answer

To determine the oxidation state of oxygen in the given compounds, we will analyze each option step by step.

### Step 1: Analyze Carbon Monoxide (CO)
- In carbon monoxide, we have:
- Let the oxidation state of carbon be \( x \).
- The oxidation state of oxygen is typically \( -2 \).

The equation for the compound is:
\[ x + (-2) = 0 \implies x - 2 = 0 \implies x = +2 \]

- Therefore, the oxidation state of oxygen in CO is \( -2 \).

### Step 2: Analyze Sulfur Dioxide (SO₂)
- In sulfur dioxide, we have:
- Let the oxidation state of sulfur be \( y \).
- The oxidation state of oxygen is \( -2 \).

The equation for the compound is:
\[ y + 2(-2) = 0 \implies y - 4 = 0 \implies y = +4 \]

- Therefore, the oxidation state of oxygen in SO₂ is \( -2 \).

### Step 3: Analyze Hydrogen Peroxide (H₂O₂)
- In hydrogen peroxide, we have:
- Let the oxidation state of oxygen be \( z \).
- The oxidation state of hydrogen is \( +1 \).

The equation for the compound is:
\[ 2(+1) + 2z = 0 \implies 2 + 2z = 0 \implies 2z = -2 \implies z = -1 \]

- Therefore, the oxidation state of oxygen in H₂O₂ is \( -1 \).

### Step 4: Analyze Ozone (O₃)
- In ozone, all three atoms are oxygen.
- The oxidation state of oxygen in elemental form (O₂, O₃) is \( 0 \).

- Therefore, the oxidation state of oxygen in O₃ is \( 0 \).

### Conclusion
- The oxidation state of oxygen is zero in **ozone (O₃)**.

### Final Answer
The oxidation state of oxygen is zero in **ozone (O₃)**.

---