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In which of the following compounds, oxy...

In which of the following compounds, oxygen exhibits +2 oxidation state ?

A

`H_(2)O`

B

`H_(2)O_(2)`

C

`OF_(2)`

D

`H_(2)SO_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine in which of the given compounds oxygen exhibits a +2 oxidation state, we will analyze each compound one by one and calculate the oxidation states of oxygen. ### Step-by-Step Solution: 1. **Identify the Compounds**: The compounds we need to analyze are H2O, H2O2, OF2, and H2SO4. 2. **Calculate Oxidation State in H2O**: - In water (H2O), hydrogen (H) has an oxidation state of +1. - The equation for the oxidation state of oxygen (O) can be set up as follows: \[ 2(+1) + x = 0 \quad \text{(where x is the oxidation state of O)} \] - Solving for x: \[ 2 + x = 0 \implies x = -2 \] - Therefore, in H2O, oxygen exhibits an oxidation state of -2. 3. **Calculate Oxidation State in H2O2**: - In hydrogen peroxide (H2O2), the oxidation state of hydrogen is still +1. - The equation for the oxidation state of oxygen can be set up as: \[ 2(+1) + 2x = 0 \] - Solving for x: \[ 2 + 2x = 0 \implies 2x = -2 \implies x = -1 \] - Therefore, in H2O2, oxygen exhibits an oxidation state of -1. 4. **Calculate Oxidation State in OF2**: - In oxygen difluoride (OF2), fluorine (F) has an oxidation state of -1. - The equation for the oxidation state of oxygen can be set up as: \[ x + 2(-1) = 0 \] - Solving for x: \[ x - 2 = 0 \implies x = +2 \] - Therefore, in OF2, oxygen exhibits an oxidation state of +2. 5. **Calculate Oxidation State in H2SO4**: - In sulfuric acid (H2SO4), hydrogen has an oxidation state of +1, and sulfur (S) typically has an oxidation state of +6. - The equation for the oxidation state of oxygen can be set up as: \[ 2(+1) + x + 6 = 0 \] - Solving for x: \[ 2 + x + 6 = 0 \implies x + 8 = 0 \implies x = -2 \] - Therefore, in H2SO4, oxygen exhibits an oxidation state of -2. ### Conclusion: After analyzing all the compounds, we find that the only compound in which oxygen exhibits a +2 oxidation state is **OF2**. ### Final Answer: **Oxygen exhibits +2 oxidation state in OF2.** ---
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