Which is non poisonous hydride ?

Options

A. `H_(2)S`
B. `H_(2)O_(2)`
C. `H_(2)Se`
D. `H_(2)Te`

Answer

To determine which hydride among the given options is non-poisonous, we need to analyze the hydrides formed by the elements of Group 16 (the chalcogens) in the periodic table. The elements in this group include oxygen (O), sulfur (S), selenium (Se), tellurium (Te), and polonium (Po).

### Step-by-Step Solution:

1. **Identify the Group 16 Elements**:
The elements in Group 16 are:
- Oxygen (O)
- Sulfur (S)
- Selenium (Se)
- Tellurium (Te)
- Polonium (Po)

2. **List the Common Hydrides**:
The common hydrides formed by these elements are:
- Water (H₂O) from Oxygen
- Hydrogen sulfide (H₂S) from Sulfur
- Hydrogen selenide (H₂Se) from Selenium
- Hydrogen telluride (H₂Te) from Tellurium
- Hydrogen polonide (H₂Po) from Polonium (less common)

3. **Assess the Toxicity of Each Hydride**:
- **H₂O (Water)**: Non-poisonous.
- **H₂S (Hydrogen sulfide)**: Poisonous, known for its rotten egg smell.
- **H₂Se (Hydrogen selenide)**: Poisonous.
- **H₂Te (Hydrogen telluride)**: Generally considered non-poisonous, although it has a foul odor.
- **H₂Po (Hydrogen polonide)**: Polonium is radioactive and hence can be considered dangerous.

4. **Conclusion**:
Among the hydrides listed, **H₂Te (Hydrogen telluride)** is the non-poisonous hydride. Therefore, the answer to the question is:
- **H₂Te (Hydrogen telluride)** is the non-poisonous hydride.

### Final Answer:
The non-poisonous hydride is **H₂Te (Hydrogen telluride)**.

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