In the hydrides of VIA elements largest bond angle and bond length is observed respectively in 

Options

A. `H_(2)O, H_(2)O`
B. `H_(2)Po, H_(2)O`
C. `H_(2)O, H_(2)Po`
D. `H_(2)S, H_(2)Se`

Answer

To solve the question regarding the hydrides of VIA group elements (Group 6A), we need to determine which hydride has the largest bond angle and which has the largest bond length.

### Step-by-Step Solution:

1. **Identify the VIA Group Elements**:
The VIA group elements include oxygen (O), sulfur (S), selenium (Se), tellurium (Te), and polonium (Po).

2. **Write the Hydrides**:
The hydrides formed by these elements are:
- H2O (water)
- H2S (hydrogen sulfide)
- H2Se (hydrogen selenide)
- H2Te (hydrogen telluride)
- H2Po (hydrogen polonide)

3. **Analyze Bond Angles**:
- The bond angle in these hydrides is influenced by the presence of lone pairs on the central atom.
- As we move down the group from oxygen to polonium, the size of the central atom increases, and the repulsion between the lone pairs decreases due to increased distance.
- The bond angle decreases down the group. Therefore, the largest bond angle will be in H2O, followed by H2S, H2Se, H2Te, and H2Po.

4. **Determine the Largest Bond Angle**:
- The largest bond angle is found in H2O (approximately 104.5°).

5. **Analyze Bond Lengths**:
- Bond length increases down the group due to the increasing atomic size of the central atom.
- Therefore, the bond lengths will be in the order: H2O < H2S < H2Se < H2Te < H2Po.

6. **Determine the Largest Bond Length**:
- The largest bond length is found in H2Po.

7. **Final Answer**:
- The largest bond angle is in H2O, and the largest bond length is in H2Po.

### Conclusion:
The answer to the question is:
- **Largest bond angle**: H2O
- **Largest bond length**: H2Po