Among hexahalides of VIA group, the stable halides are

Options

A. hexa iodides
B. hexa bromides
C. hexa chlorides
D. hexa fluorides

Answer

To determine which hexahalides of the VIA group elements are stable, we need to analyze the stability of the hexahalides formed with different halogens. The VIA group elements include oxygen, sulfur, selenium, tellurium, and polonium. The halogens involved are fluorine, chlorine, bromine, and iodine.

### Step-by-Step Solution:

1. **Identify the Group Elements**:
The VIA group elements are:
- Oxygen (O)
- Sulfur (S)
- Selenium (Se)
- Tellurium (Te)
- Polonium (Po)

2. **Identify the Halogens**:
The halogens from Group 17 are:
- Fluorine (F)
- Chlorine (Cl)
- Bromine (Br)
- Iodine (I)

3. **Formulate the Hexahalides**:
The hexahalides can be represented as MX₆, where M is the VIA group element and X is the halogen. The possible hexahalides are:
- Hexafluoride (MF₆)
- Hexachloride (MCl₆)
- Hexabromide (MBr₆)
- Hexaiodide (MI₆)

4. **Analyze Stability**:
The stability of these hexahalides depends on the size of the halogen atoms. As we move down the group of halogens from fluorine to iodine, the atomic size increases:
- Fluorine (smallest) → Chlorine → Bromine → Iodine (largest)

5. **Conclusion on Stability**:
- **Hexafluoride (MF₆)**: Most stable due to the small size of fluorine, allowing six fluorine atoms to be accommodated around the central atom.
- **Hexachloride (MCl₆)**: Less stable than MF₆ but more stable than MBr₆ and MI₆.
- **Hexabromide (MBr₆)**: Less stable than MCl₆.
- **Hexaiodide (MI₆)**: Least stable due to the large size of iodine, making it difficult to accommodate six iodine atoms.

6. **Final Answer**:
The most stable hexahalide among the options is **Hexafluoride (MF₆)**.