`SO_(2)` forms an addition compound sulphuryl chloride with `Cl_(2)` in presence of

Options

A. Charcoal
B. `C Cl_(4)`
C. `H^(+)//K_(2)Cr_(2)O_(7)`
D. `H^(+)//KMnO_(4)`

Answer

To solve the problem of how sulfur dioxide (SO₂) forms an addition compound with chlorine (Cl₂) to produce sulfuryl chloride (SO₂Cl₂), we will follow these steps:

### Step 1: Understand the Reaction
We start with sulfur dioxide (SO₂) and chlorine gas (Cl₂). The reaction involves the addition of chlorine to sulfur dioxide.

**Hint:** Identify the reactants and the product of the reaction.

### Step 2: Write the Chemical Equation
The chemical equation for the reaction can be written as:
\[ \text{SO}_2 (g) + \text{Cl}_2 (g) \rightarrow \text{SO}_2\text{Cl}_2 (l) \]

**Hint:** Write the balanced equation for the reaction to visualize the transformation.

### Step 3: Identify the Type of Reaction
This is an addition reaction where two reactants combine to form a single product. In this case, chlorine is added to sulfur dioxide.

**Hint:** Recognize the type of reaction to understand the mechanism involved.

### Step 4: Determine the Catalyst Required
From the options given, we need to identify which catalyst facilitates this reaction. The options provided are:
1. Charcoal
2. CCl₄
3. H⁺ in K₂Cr₂O₇
4. H⁺ in KMnO₄

The correct catalyst for this reaction is charcoal.

**Hint:** Consider the role of catalysts in chemical reactions and how they can influence the reaction pathway.

### Step 5: Conclude the Reaction
Thus, the final conclusion is that sulfur dioxide reacts with chlorine in the presence of charcoal to form sulfuryl chloride.

**Final Answer:** The catalyst required for the formation of sulfuryl chloride (SO₂Cl₂) from sulfur dioxide (SO₂) and chlorine (Cl₂) is **charcoal**.

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