What is the number of sigma and pi bonds present in `H_(2)SO_(4)` molecule ? 

Options

A. `6sigma and 2pi`
B. `6sigma and 0pi`
C. `2sigma and 4pi`
D. `2sigma and 2pi`

Answer

To determine the number of sigma and pi bonds in the molecule H₂SO₄ (sulfuric acid), we will follow these steps:

### Step 1: Draw the Lewis Structure of H₂SO₄
- Start by identifying the central atom, which is sulfur (S).
- Sulfur is bonded to four oxygen atoms (O). Two of these oxygen atoms are bonded to hydrogen (H) atoms.
- The structure can be represented as follows:
```
O
||
H - S - O - H
|
O
```

### Step 2: Identify the Types of Bonds
- In the structure, we can see:
- There are two H-O single bonds.
- There are two S=O double bonds.

### Step 3: Count Sigma Bonds
- Each single bond (H-O) is a sigma bond.
- Each double bond (S=O) consists of one sigma bond and one pi bond.
- Therefore, we count:
- 2 sigma bonds from the H-O bonds.
- 2 sigma bonds from the S=O double bonds.

### Step 4: Count Pi Bonds
- For the double bonds (S=O), there is one pi bond for each double bond.
- Thus, there are 2 pi bonds from the two S=O double bonds.

### Step 5: Total Count of Sigma and Pi Bonds
- Total sigma bonds = 2 (from H-O) + 2 (from S=O) = 4 sigma bonds.
- Total pi bonds = 2 (from S=O double bonds).

### Final Answer
- The total number of sigma bonds in H₂SO₄ is 6, and the total number of pi bonds is 2.

### Summary
- **Sigma Bonds**: 6
- **Pi Bonds**: 2