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In a compound of sulphur, the sulphur at...

In a compound of sulphur, the sulphur atom is in second excited state. The possible hybridisation of sulphur is 

A

`sp^(2)`

B

`sp^(3)`

C

`sp^(3)d^(2)`

D

`sp^(2)(or) sp^(3) (or) sp^(3)d^(2)`

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To determine the possible hybridization of sulfur in its second excited state, we can follow these steps: ### Step 1: Understand the Ground State Configuration of Sulfur Sulfur (S) has the atomic number 16. The ground state electron configuration is: - 1s² 2s² 2p⁶ 3s² 3p⁴ In the outermost shell (n=3), sulfur has: - 2 electrons in the 3s orbital - 4 electrons in the 3p orbital ### Step 2: Identify the Excited State Configuration In the second excited state, two electrons from the outer shell will be promoted to a higher energy level. The electrons can be excited as follows: - One electron remains in the 3s orbital. - Three electrons remain in the 3p orbital. - Two electrons get excited to the 3d orbital (which is vacant). The excited state configuration can be represented as: - 3s¹ 3p³ 3d² ### Step 3: Determine the Hybridization In this excited state configuration (3s¹ 3p³ 3d²), we have: - 1 electron in the 3s orbital - 3 electrons in the 3p orbitals - 2 electrons in the 3d orbitals This results in a total of 6 half-filled orbitals (1 from 3s, 3 from 3p, and 2 from 3d). The hybridization that corresponds to this configuration is: - **sp³d²** ### Conclusion Thus, the possible hybridization of sulfur in its second excited state is **sp³d²**.
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